PP1 (Shorter) Quant Section 1 (Medium) Q1

<p><span style="font-size:20px;"><span style="color:#8e44ad;">Deductions from the Given Information</span></span></p> <p>Because $O$ is the center of the circle, we can see that $OR$ and $OS$ are both radii of the circle. That of course means that $\angle R$ and $\angle S$ are equivalent (see diagram below).</p> <p style="text-align: center;"><img alt="" src="https://gregmatapi.s3.amazonaws.com/media/misc/files/question1_a.PNG" style="height: 284px; width: 300px;" /></p> <p>From this, we can make another deduction. We know that the three angles of a triangle sum to $180$ degrees, giving us this equation below:&nbsp;</p> <p style="text-align: center;">$$60 + x + x =180$$</p> <p>Solving the equation, we see that $x$ is equal to $60$ and triangle $ROS$ is equilateral. The given information tells us that the perimeter of $ROS$ is $6$, so we can conclude the radius is $2$ (see diagram below).</p> <p style="text-align: center;"><img alt="" src="https://gregmatapi.s3.amazonaws.com/media/misc/files/question1_b.PNG" style="width: 300px; height: 277px;" /></p> <p><span style="color:#27ae60;"><span style="font-size:20px;">Solving the Problem</span></span></p> <p><strong>Quantity A</strong>&nbsp;is the circumference of the circle, which can now be found since we deduced the radius ($r=2$) from the given information.</p> <p style="text-align: center;">$$2 \pi r = 4\pi = \approx 12.56$$</p> <p>In comparison with&nbsp;<strong>Quantity B</strong>, $12$, we can clearly see that <strong><span style="color:#27ae60;">Quantity A is larger</span></strong>.</p>