PP1 (Shorter) Quant Section 1 (Medium) Q3

<p><span style="color:#8e44ad;"><span style="font-size:20px;">Deductions from the Given Information</span></span></p> <p>The deduction for this problem is rather obvious but very important. $x$ can take any value as long as it&#39;s greater than $6$ and less than $7$. This is so important is because it tells us what values we should test. Remember, you don&#39;t want to test two values that are bunched together. For example, you wouldn&#39;t want to test $6.4$ and $6.5$. Instead, you should test values that are as spread out as possible to figure out what&#39;s going on.</p> <p><span style="font-size:20px;"><span style="color:#27ae60;">Solving the Problem</span></span></p> <p>To solve this problem, I recommend testing the following two values for $x$: $6.1$ and $6.9$. Notice how these two numbers are quite spread out and don&#39;t violate the given information. Let&#39;s see what happens with our first value:</p> <p style="text-align: center;">$$\frac{6.1}{8} = 0.7625$$</p> <p>Let&#39;s test out the second value:</p> <p style="text-align: center;">$$\frac{6.9}{8} = 0.8625$$</p> <p>In the first case,&nbsp;<strong>Quantity B&nbsp;</strong>is larger than&nbsp;<strong>Quantity A.&nbsp;</strong>In the second case,&nbsp;<strong>Quantity A</strong>&nbsp;is larger. Thus, the answer is <strong><span style="color:#27ae60;">D, It cannot be determined</span></strong>.</p>