PP1 (Shorter) Quant Section 2 (Easy) Q11

<p><span style="color:#27ae60;"><span style="font-size:20px;">Solving the Problem</span></span></p> <p>We know that the middle number in a list of 3 numbers will be the median, so our list would look something like this:</p> <p>$x, 8, y$</p> <ul> <li>$x$ is the least number in the list</li> <li>$y$ is the greatest number in the list</li> </ul> <p>We are told that the greatest number is 10 greater than the least number, so we can deduce that:</p> <ul> <li>$y = x + 10$</li> <li>$x = y - 10$</li> </ul> <p>So, we can rewrite our list in terms of y:</p> <p>$y-10, 8, y$</p> <p>We also know the following about the relation between mean and sum:</p> <p>$sum = mean * number of values$</p> <p>Since we know the mean and the number of values, we can work out the sum:</p> <p>$sum = 8 * 3$</p> <p>$sum = 24$</p> <p>We also know that 24 will be equal to the sum of every item in our list, so we can solve for y to find the greatest number in the list:</p> <ul> <li>$24 = (y-10) + 8 + y$</li> <li>$24 = 2y - 10 + 8$</li> <li>$24 = 2y - 2$</li> <li>$26 = 2y$</li> <li>$13 = y$</li> </ul> <p>So, the answer will be <span style="color:#27ae60;">13</span>.</p>