<p><span style="color:#27ae60;"><span style="font-size:20px;">Solving the Problem</span></span></p>
<p>We can start by looking at the first equation: $(x+2)(x-3) = 0$</p>
<p>We know from this that either $x+2=0$ or $x-3=0$</p>
<p>So, $x$ could either be $-2$ or $3.$</p>
<p>Since we are told that $x>\frac{1}{2}$, we know that $x$ must be $3$.</p>
<p>Now, we can solve $x^{-2}$, which is the same as $\frac{1}{x^2}$</p>
<p>If we plug in $x=3$, we get the result of $\frac{1}{3^2}$ which is $\frac{1}{9}$.</p>
<p>So, the answer must be <span style="color:#27ae60;">D</span>.</p>