<p><span style="color:#27ae60;"><span style="font-size:20px;">Solving the Problem</span></span></p>
<p>This is a question that is best solved by <span style="color:#8e44ad;"><strong>Having a System</strong></span>. We can first categorize our fruits:</p>
<table border="1" cellpadding="1" cellspacing="1" style="width:500px;">
<thead>
<tr>
<th scope="col">Fruit Type</th>
<th scope="col">Fruit Name</th>
<th scope="col">Fruit Price in $ per pound</th>
</tr>
</thead>
<tbody>
<tr>
<td>Apple</td>
<td>Apple Variety 1 (A1)</td>
<td>1.00</td>
</tr>
<tr>
<td>Apple</td>
<td>Apple Variety 2 (A2)</td>
<td>1.25</td>
</tr>
<tr>
<td>Orange</td>
<td>Orange Variety 1 (O1)</td>
<td>1.25</td>
</tr>
<tr>
<td>Orange</td>
<td>Orange Variety 2 (O2)</td>
<td>1.50</td>
</tr>
</tbody>
</table>
<p>Now, we can figure out what the total price could be for different combinations of these varieties:</p>
<table border="1" cellpadding="1" cellspacing="1" style="width:500px;">
<thead>
<tr>
<th scope="row"> </th>
<th scope="col">3 Pounds of A1</th>
<th scope="col">3 Pounds of A2</th>
</tr>
</thead>
<tbody>
<tr>
<th scope="row">2 Pounds of O1</th>
<td>$3(1.00)+2(1.25)=5.50$</td>
<td>$3(1.25)+2(1.25)=6.25$ <span style="color:#27ae60;">C</span></td>
</tr>
<tr>
<th scope="row">2 Pounds of O2</th>
<td>$3(1.00)+2(1.50)=6.00$ <span style="color:#27ae60;">B</span></td>
<td>$3(1.25)+2(1.50)=6.75$ <span style="color:#27ae60;">E</span></td>
</tr>
</tbody>
</table>
<p>From this, we can see that <span style="color:#27ae60;">B</span>, <span style="color:#27ae60;">C</span>, and <span style="color:#27ae60;">E</span> are all valid answers.</p>