<p><span style="color:#27ae60;"><span style="font-size:20px;">Solving the Problem</span></span></p>
<p>We should first deduce the fact that the cars have been ordered by cost in ascending order, and grouped together into the four price range categories shown in the table. It's useful to also consider which cars are in each of the groups:</p>
<ul>
<li>Cars $1$ to $7$ are in the first group</li>
<li>Cars $8$ to $17$ are in the second group</li>
<li>Cars $18$ to $25$ are in the third group</li>
<li>Cars $26$ to $31$ are in the fourth group</li>
</ul>
<p>Since we have $31$ cars, the median value would be $\frac{31+1}{2} = 16th\,car$. This would be in the second row of the table, between car $7$ (at the end of the first category) and car $17$ (at the end of the second category).</p>
<p>We don't know the actual costs of the cars, so the $16th$ car could cost anywhere in the range specified for the second category: $\$5000\,to\,\$7499$.</p>
<p>So, $\$5500,\$6500$, and $\$7000$ could all be valid prices for the $16th$ car.</p>
<p>Therefore, the correct answers would be <span style="color:#27ae60;">A, B, and C</span>.</p>